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How the calculation works
Calculate frequency, period and duty cycle for a classic 555 astable oscillator. The tool converts the form units and presents the result using readable engineering notation.
f ≈ 1.44 / ((R1 + 2R2)C)
Example
R1 1 kΩ, R2 10 kΩ and C 10 µF gives about 6.9 Hz.
How to interpret the result
- The classic circuit does not normally reach exactly 50% duty cycle without an added diode or different topology.
- R and C tolerance directly affects frequency.
- At long intervals capacitor leakage may dominate the result.
Limitations and safe use
The result uses a simplified model. Check tolerance, temperature, absolute ratings and the component datasheet.
FAQ
Is the result saved?
The latest result may be stored locally in this browser, but it is not sent to LutujTo.
Can I use the result in a project?
Yes, but select a real component with margin and confirm its ratings in the datasheet.